Question 3: The sum of 2 + 4 + 6 + 8 + … + 298 + 300 is:

The number of terms of the given sum is: (300−2):2+1=150(terms)

Hence 2+4+6+8+…+298+300=(300+2).150:2=22650<45300

So the sum to find has the last digit is 0

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Question 3: The sum of 2 + 4 + 6 + 8 + … + 298 + 300 is:

The number of terms of the given sum is: (300−2):2+1=150(terms)

Hence 2+4+6+8+…+298+300=(300+2).150:2=22650<45300

So the sum to find has the last digit is 0

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